Electro Magnetic Induction And Alternating Currents Question 33

Question: The reactance of a $ 25,\mu F $ capacitor at the ac frequency of 4000 Hz is

Options:

A) $ \frac{5}{\pi } $ ohm

B) $ \sqrt{\frac{5}{\pi }} $ ohm

C) 10 ohm

D) $ \sqrt{10} $ ohm

Show Answer

Answer:

Correct Answer: A

Solution:

$ X_{C}=\frac{1}{2\pi \nu C}=\frac{1}{2\pi \times 4000\times 25\times {{10}^{-6}}}=\frac{5}{\pi }\Omega $



NCERT Chapter Video Solution

Dual Pane