SATHEE: Electro Magnetic Induction And Alternating Currents Question 323

Electro Magnetic Induction And Alternating Currents Question 323

Question: An inductor of 2 henry and a resistance of 10 ohms are connected in series with a battery of 5 volts. The initial rate of change of current is [MP PMT 2001]

Options:

A) 0.5 amp/sec

B) 2.0 amp/sec

C) 2.5 amp/sec

D) 0.25 amp/sec

Show Answer

Answer:

Correct Answer: C

Solution:

$i = i_{0} (1 - e^{\frac{- R t}{L}}) \Rightarrow \frac{d i}{d t} = \frac{d}{d t} i_{0} - \frac{d}{d t} i_{0} e^{\frac{- R t}{L}}$

$\Rightarrow \frac{d i}{d t} = 0 - i_{0} (- \frac{R}{L}) e^{- \frac{R t}{L}} = \frac{i_{0} R}{L} e^{- \frac{R t}{L}}$

Initially, $t = 0 \Rightarrow \frac{d i}{d t} = \frac{i_{0} \times R}{L} = \frac{E}{L} = \frac{5}{2} = 2.5 a m p / s e c .$

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Electro Magnetic Induction And Alternating Currents Question 323

Question: An inductor of 2 henry and a resistance of 10 ohms are connected in series with a battery of 5 volts. The initial rate of change of current is [MP PMT 2001]

Options:

Answer:

Solution:

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