SATHEE: Electro Magnetic Induction And Alternating Currents Question 322

Electro Magnetic Induction And Alternating Currents Question 322

Question: A conducting rod of length 2l is rotating with constant angular speed w about its perpendicular bisector. A uniform magnetic field $\vec{B}$ exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is [MP PET 2001]

Options:

A) Bwl2

B) $\frac{1}{2} B ω l^{2}$

C) $\frac{1}{8} B ω l^{2}$

D) Zero

Show Answer

Answer:

Correct Answer: D

Solution:

Potential difference between O and A is $V_{0} - V_{A} = \frac{1}{2} B l^{2} ω$ O and B is $V_{0} - V_{B} = \frac{1}{2} B l^{2} ω$ so $V_{A} - V_{B} = 0$

Electro Magnetic Induction And Alternating Currents Question 322

Question: A conducting rod of length 2l is rotating with constant angular speed w about its perpendicular bisector. A uniform magnetic field $\vec{B}$ exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is [MP PET 2001]

Options:

Answer:

Solution:

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Electro Magnetic Induction And Alternating Currents Question 322

Question: A conducting rod of length 2l is rotating with constant angular speed w about its perpendicular bisector. A uniform magnetic field B→ exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is [MP PET 2001]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: A conducting rod of length 2l is rotating with constant angular speed w about its perpendicular bisector. A uniform magnetic field $\vec{B}$ exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is [MP PET 2001]