Electro Magnetic Induction And Alternating Currents Question 322

Question: A conducting rod of length 2l is rotating with constant angular speed w about its perpendicular bisector. A uniform magnetic field $ \overrightarrow{B} $ exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is [MP PET 2001]

Options:

A) Bwl2

B) $ \frac{1}{2}B\omega l^{2} $

C) $ \frac{1}{8}B\omega l^{2} $

D) Zero

Show Answer

Answer:

Correct Answer: D

Solution:

Potential difference between O and A is $ V_{0}-V_{A}=\frac{1}{2}Bl^{2}\omega $ O and B is $ V_{0}-V_{B}=\frac{1}{2}Bl^{2}\omega $ so $ V_{A}-V_{B}=0 $



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