Electro Magnetic Induction And Alternating Currents Question 279

Question: A transformer with efficiency 80% works at 4 kW and 100 V. If the secondary voltage is 200 V, then the primary and secondary currents are respectively [Kerala PMT 2005]

Options:

A) 40 A, 16 A

B) 16 A, 40 A

C) 20 A, 40 A

D) 40 A, 20 A

Show Answer

Answer:

Correct Answer: A

Solution:

$ \eta =\frac{\text{output},\text{power}}{\text{input},\text{power}}=\frac{E_{s}I_{s}}{E_{p}I_{p}} $

Þ $ \frac{80}{100}=\frac{200\times I_{s}}{4\times 10^{3}} $

Þ $ I_{S}=\frac{80}{100}\times \frac{4\times 1000}{200}=16A $ Also, $ E_{p}I_{p}=4KW $

Þ $ I_{p}=\frac{4\times 10^{3}}{100}=40A $



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