SATHEE: Electro Magnetic Induction And Alternating Currents Question 251

Electro Magnetic Induction And Alternating Currents Question 251

Question: A 100% efficient transformer has 100 turns in the primary and 25 turns in its secondary coil. If the current in the secondary coil is 4 amp, then the current in the primary coil is [MP PMT 1990]

Options:

A) 1 amp

B) 4 amp

C) 8 amp

D) 16 amp

Show Answer

Answer:

Correct Answer: A

Solution:

For 100% efficient transformer

$V_{s} i_{s} = V_{p} i_{p} \Rightarrow \frac{V_{s}}{V_{p}} = \frac{i_{p}}{i_{s}} = \frac{N_{s}}{N_{p}}$
$\Rightarrow \frac{i_{p}}{4} = \frac{25}{100} \Rightarrow i_{p} = 1 A$

Electro Magnetic Induction And Alternating Currents Question 251

Question: A 100% efficient transformer has 100 turns in the primary and 25 turns in its secondary coil. If the current in the secondary coil is 4 amp, then the current in the primary coil is [MP PMT 1990]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Electro Magnetic Induction And Alternating Currents Question 251

Question: A 100% efficient transformer has 100 turns in the primary and 25 turns in its secondary coil. If the current in the secondary coil is 4 amp, then the current in the primary coil is [MP PMT 1990]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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