Electro Magnetic Induction And Alternating Currents Question 235
Question: The number of turns in the coil of an ac generator is 5000 and the area of the coil is $ 0.25,m^{2} $ . The coil is rotated at the rate of 100 cycles/sec in a magnetic field of 0.2 $ W/m^{2} $ . The peak value of the emf generated is nearly [AMU 1995]
Options:
A) 786 kV
B) 440 kV
C) 220 kV
D) 157.1 Kv
Show Answer
Answer:
Correct Answer: D
Solution:
$ e_{0}=\omega NBA=(2\pi \nu )\ NBA $ $ =2\times 3.14\times 1000\times 5000\times 0.2\times 0.25 $ = 157 kV
