SATHEE: Electro Magnetic Induction And Alternating Currents Question 222

Electro Magnetic Induction And Alternating Currents Question 222

Question: A 220 volts input is supplied to a transformer. The output circuit draws a current of 2.0 ampere at 440 volts. If the efficiency of the transformer is 80%, the current drawn by the primary windings of the transformer is

Options:

A) 3.6 ampere

B) 2.8 ampere

C) 2.5 ampere

D) 5.0 ampere

Show Answer

Answer:

Correct Answer: D

Solution:

$\frac{V_{2}}{V_{1}} = 0.8 \frac{I_{1}}{I_{2}} \Rightarrow \frac{V_{2} I_{2}}{V_{1} I_{1}} = 0.8$

$V_{1} = 220 V, I_{2} = 2.0 A, V_{2} = 440 V$

$I_{1} = \frac{V_{2} I_{2}}{V_{1}} \times \frac{10}{8} = \frac{440 \times 2 \times 10}{220 \times 8} = 5 A$

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Electro Magnetic Induction And Alternating Currents Question 222

Question: A 220 volts input is supplied to a transformer. The output circuit draws a current of 2.0 ampere at 440 volts. If the efficiency of the transformer is 80%, the current drawn by the primary windings of the transformer is

Options:

Answer:

Solution:

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