SATHEE: Electro Magnetic Induction And Alternating Currents Question 208

Electro Magnetic Induction And Alternating Currents Question 208

Question: The primary and secondary coil of a transformer have 50 and 1500 turns respectively. If the magnetic flux $ϕ$ linked with the primary coil is given by $ϕ = ϕ_{0} + 4 t$ , where $ϕ$ is in webers, t is time in seconds and $ϕ_{0}$ is a constant, the output voltage across the secondary con is

Options:

A) 120 volts

B) 220 volts

C) 30 volts

D) 90 volts

Show Answer

Answer:

Correct Answer: A

Solution:

Since $\frac{V_{s}}{V_{p}} = \frac{N_{s}}{N_{p}}$

Where $N_{s}$ = No. of turns across primary coil = 50

$N_{p}$ = No. of turns across secondary coil = 1500 and

$V_{p} = \frac{d ϕ}{d t} = \frac{d}{d t} (ϕ_{0} + 4 t) = 4 \Rightarrow V = \frac{1500}{50} \times 4$ =120 V

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Electro Magnetic Induction And Alternating Currents Question 208

Question: The primary and secondary coil of a transformer have 50 and 1500 turns respectively. If the magnetic flux ϕ linked with the primary coil is given by ϕ=ϕ0+4t , where ϕ is in webers, t is time in seconds and ϕ0 is a constant, the output voltage across the secondary con is

Options:

Answer:

Solution:

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