Electro Magnetic Induction And Alternating Currents Question 206
Question: In an LCR circuit as shown below both switches are open initially. Now switch $ S_{1} $ is closed, $ S_{2} $ kept open. (q is charge on the capacitor and $ \tau =RC $ is Capacitive time constant). Which of the following statements is correct?
Options:
A) At, t=0, q=CV (1-e)
B) At, $ t=\tau $ , $ q=CV/2 $
C) At, $ t=2\tau $ , $ q=CV(1-{{e}^{-e}}) $
D) At, $ t=2\tau $ , $ q=CV(1-{{e}^{-1}}) $
Show Answer
Answer:
Correct Answer: C
Solution:
- Charge on he capacitor at any time t is given by $ q=CV\text{ (1}-{{e}^{-t/\tau }})att=2\tau $ $ q=CV\text{ (1-}{{\text{e}}^{-2}}\text{)} $
