SATHEE: Electro Magnetic Induction And Alternating Currents Question 203

Electro Magnetic Induction And Alternating Currents Question 203

Question: A fully charged capacitor C with initial charge $q_{0}$ is connected to a coil of self-inductance L at $t = 0.$ The time at which the energy is stored equally between the electric and the magnetic fields is:

Options:

A) $\frac{π}{4} \sqrt{L C}$

B) $2 π \sqrt{L C}$

C) $\sqrt{L C}$

D) $π \sqrt{L C}$

Show Answer

Answer:

Correct Answer: A

Solution:

Energy stored in magnetic field = $\frac{1}{2}, L i^{2}$

Energy stored in electric field = $\frac{1}{2}, \frac{q^{2}}{C}$
$∴ \frac{1}{2}, L i^{2} = \frac{1}{2}, \frac{q^{2}}{C}$

Also $q = q_{0}$ cos $ω, t$ and $ω = \frac{1}{\sqrt{L C}}$

On solving $t = \frac{π}{4}, \sqrt{L C}$

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Electro Magnetic Induction And Alternating Currents Question 203

Question: A fully charged capacitor C with initial charge q0 is connected to a coil of self-inductance L at t=0. The time at which the energy is stored equally between the electric and the magnetic fields is:

Options:

Answer:

Solution:

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Question: A fully charged capacitor C with initial charge $q_{0}$ is connected to a coil of self-inductance L at $t = 0.$ The time at which the energy is stored equally between the electric and the magnetic fields is: