SATHEE: Electro Magnetic Induction And Alternating Currents Question 201

Electro Magnetic Induction And Alternating Currents Question 201

Question: In the circuit shown below, the key K is closed at t=0. The current through the battery is

Options:

A) $\frac{V R_{1} R_{2}}{\sqrt{R_{1}^{2} + R_{2}^{2}}}$ at t=0 and $\frac{V}{R_{2}}$ at $t = \infty$

B) $\frac{V}{R_{2}}$ at t=0 and $\frac{V (R_{1} + R_{2})}{R_{1} R_{2}}$ at $t = \infty$

C) $\frac{V}{R_{2}}$ at t=0 and $\frac{V R_{1} R_{2}}{\sqrt{R_{1}^{2} + R_{2}^{2}}}$ at $t = \infty$

D) $\frac{V (R_{1} + R_{2})}{R_{1} R_{2}}$ at t=0 and $\frac{V}{R_{2}}$ at $t = \infty$

Show Answer

Answer:

Correct Answer: C

Solution:

At t = 0, no current will flow through L and $R_{1}$

$∴$ Current through battery $=, \frac{V}{R_{2}}$

At $t = \infty$ effective resistance, $R_{e f f} = \frac{R_{1} R_{2}}{R_{1} + R_{2}}$

$∴$ Current through battery $= \frac{V}{R_{e f f}} = \frac{V, (R_{1} R_{2})}{(R_{1} + R_{2})}$

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Electro Magnetic Induction And Alternating Currents Question 201

Question: In the circuit shown below, the key K is closed at t=0. The current through the battery is

Options:

Answer:

Solution:

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