Electro Magnetic Induction And Alternating Currents Question 188

Question: What is the amount of power delivered by the ac source in the circuit shown (in watts).

Options:

A) 500 watt

B) 1014 watt

C) 1514 watt

D) 2013 watt

Show Answer

Answer:

Correct Answer: C

Solution:

  • $ {i _{1,rms}}=\frac{E _{rms}}{\sqrt{X _{C}^{2}+R _{1}^{2}}}=\frac{130}{13}=10A $

    $ {i _{2,rms}}=\frac{E _{rms}}{\sqrt{X _{L}^{2}+R _{2}^{2}}}=13,A $

    Power dissipated $ =i^{2} _{1,rms},R _{1}+i^{2} _{2,rms}R _{2}=10^{2}\times 5+13^{2}+6 $ = power delivered by battery $ =500+169\times 6=1514,watt $



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