Electro Magnetic Induction And Alternating Currents Question 179

Question: In the circuit shown, the symbols have their usual meanings. The cell has emf E. X is initially joined to V for a long time. Then, disjoined to Z The maximum charge on C at any later time will be

Options:

A) $ \frac{E}{R\sqrt{LC}} $

B) $ \frac{ER}{2\sqrt{LC}} $

C) $ \frac{E\sqrt{LC}}{2R} $

D) $ \frac{E\sqrt{LC}}{R} $

Show Answer

Answer:

Correct Answer: D

Solution:

  • Current in inductor $ =\frac{E}{R} $
    $ \therefore $ its energy $ =\frac{1}{2}\frac{LE^{2}}{R^{2}} $ Same energy is later stored in capacitor $ \frac{Q^{2}}{2C}=\frac{1}{2}\frac{LE^{2}}{R^{2}}\Rightarrow Q=\sqrt{LC}\frac{E}{R} $


NCERT Chapter Video Solution

Dual Pane