SATHEE: Electro Magnetic Induction And Alternating Currents Question 165

Electro Magnetic Induction And Alternating Currents Question 165

Question: The equation of AC voltage is $E = 220, \sin, (ω t + π / 6)$ and the A.C. current $I = 10, \sin, (ω t + π / 6)$ . The average power dissipated is

Options:

A) 150 W

B) 550 W

C) 250 W

D) 50 W

Show Answer

Answer:

Correct Answer: B

Solution:

We know that, $Z = \frac{E_{0}}{I_{0}}$

Given, $E_{0} = 220$ and $I_{0} = 10$

So $Z = \frac{220}{10} = 22, o h m$

$ϕ = [\frac{π}{6} - (- \frac{π}{6})] = \frac{π}{3}$

$P_{a} = \frac{E_{0}}{\sqrt{2}} \times \frac{I_{0}}{\sqrt{2}} \times \cos$

$ϕ = \frac{220}{\sqrt{2}} \times \frac{10}{\sqrt{2}} \times \cos, \frac{π}{3}$

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Electro Magnetic Induction And Alternating Currents Question 165

Question: The equation of AC voltage is E=220,sin,(ωt+π/6) and the A.C. current I=10,sin,(ωt+π/6) . The average power dissipated is

Options:

Answer:

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Question: The equation of AC voltage is $E = 220, \sin, (ω t + π / 6)$ and the A.C. current $I = 10, \sin, (ω t + π / 6)$ . The average power dissipated is