SATHEE: Electro Magnetic Induction And Alternating Currents Question 152

Electro Magnetic Induction And Alternating Currents Question 152

Question: In a series circuit $C = 2 μ F,, L = 1 m H$ and $R = 10, Ω,$ when the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be

Options:

A) 1 : 1

B) 1 : 2

C) 2 : 1

D) 1 : 5

Show Answer

Answer:

Correct Answer: D

Solution:

Current will be maximum in the condition of resonance so $

{i_{\max }}=\frac{V}{R}=\frac{V}{10}A $E n e r g y s t o r e d i n t h e c o i l$ W_{L}=\frac{1}{2}Li_{\max }^{2} $

$= \frac{1}{2} L {(\frac{E}{10})}^{2}$

$= \frac{1}{2} \times 10^{- 3} (\frac{E^{2}}{100})$

$= \frac{1}{2} \times 10^{- 5} E^{2} j o u l e$

$∴$ Energy stored in the capacitor $W_{C} = \frac{1}{2} C E^{2} = \frac{1}{2} \times 2 \times 10^{- 6} E^{2} = 10^{- 6} E^{2} j o u l e$

$∴ \frac{W_{C}}{W_{L}} = \frac{1}{5}$

Electro Magnetic Induction And Alternating Currents Question 152

Question: In a series circuit $C = 2 μ F,, L = 1 m H$ and $R = 10, Ω,$ when the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be

Options:

Answer:

Solution:

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Electro Magnetic Induction And Alternating Currents Question 152

Question: In a series circuit C=2μF,,L=1mH and R=10,Ω, when the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: In a series circuit $C = 2 μ F,, L = 1 m H$ and $R = 10, Ω,$ when the current in the circuit is maximum, at that time the ratio of the energies stored in the capacitor and the inductor will be