Electro Magnetic Induction And Alternating Currents Question 143

Question: Match the following Currents r.m.s. values (1) x0sinω,t (i) x0 (2) x0sinω,tcosω,t (ii) x02 (3) x0sinω,t+x0cosω,t (iii) x0(22)

Options:

A) 1. (i), 2. (ii), 3. (iii)

B) 1. (ii), 2. (iii), 3. (i)

C) 1. (i), 2. (iii), 3. (ii)

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

  1. rms value = x02

  2. x0sinωtcosωt=x02sin2ωtrms value=x022

  3. x0sinωt+x0cosωtrms value=(x02)2+(x02)2 =x02=x0



NCERT Chapter Video Solution

Dual Pane