SATHEE: Electro Magnetic Induction And Alternating Currents Question 104

Electro Magnetic Induction And Alternating Currents Question 104

Question: A resistance of 20 ohms is connected to a source of an alternating potential $V = 220 \sin (100 π t)$ . The time taken by the current to change from its peak value to r.m.s value is [MP PET 2001]

Options:

A) 0.2 sec

B) 0.25 sec

C) $25 \times 10^{- 3}$ sec

D) $2.5 \times 10^{- 3}$ sec

Show Answer

Answer:

Correct Answer: D

Solution:

Peak value to r.m.s. value means, current becomes $\frac{1}{\sqrt{2}}$ times. So from $i = i_{0} \sin 100 π t \Rightarrow \frac{1}{\sqrt{2}} \times i_{0} = i_{0} \sin 100 π t$
$\Rightarrow \sin \frac{π}{4} = \sin 100 π t \Rightarrow t = \frac{1}{400} s e c$ $= 2.5 \times 10^{- 3} s e c .$

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Electro Magnetic Induction And Alternating Currents Question 104

Question: A resistance of 20 ohms is connected to a source of an alternating potential V=220sin⁡(100πt) . The time taken by the current to change from its peak value to r.m.s value is [MP PET 2001]

Options:

Answer:

Solution:

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Question: A resistance of 20 ohms is connected to a source of an alternating potential $V = 220 \sin (100 π t)$ . The time taken by the current to change from its peak value to r.m.s value is [MP PET 2001]