Atoms And Nuclei Question 95
Question: The ratio of the largest to shortest wavelengths in Lyman series of hydrogen spectra is [EAMCET (Med.) 2000]
Options:
A) $ \frac{25}{9} $
B) $ \frac{17}{6} $
C) $ \frac{9}{5} $
D) $ \frac{4}{3} $
Show Answer
Answer:
Correct Answer: D
Solution:
For Lyman series $ \frac{1}{{\lambda_{\max }}}=R[ \frac{1}{1^{2}}-\frac{1}{2^{2}} ]=\frac{3}{4}R $ and $ \frac{1}{{\lambda_{\min }}}=R[ \frac{1}{1^{2}}-\frac{1}{{{\infty }^{2}}} ]=\frac{R}{1}\Rightarrow \frac{{\lambda_{\max }}}{{\lambda_{\min }}}=\frac{4}{3} $
