Atoms And Nuclei Question 82

Question: The wavelength of radiation emitted is λ0 when an electron jumps from the third to the second orbit of hydrogen atom. For the electron jump from the fourth to the second orbit of the hydrogen atom, the wavelength of radiation emitted will be [SCRA 1998; MP PET 2001; MH CET 2003]

Options:

A) 1625λ0

B) 2027λ0

C) 2720λ0

D) 2516λ0

Show Answer

Answer:

Correct Answer: B

Solution:

1λ=R,[1n121n22]
Þ 1λ32=R,[1(2)21(3)2]=5R36 and 1λ42=R[1(2)21(4)2]=3R16 \ λ42λ32=2027
Þ λ42=2027λ0



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