SATHEE: Atoms And Nuclei Question 74

Atoms And Nuclei Question 74

Question: The wavelength of Lyman series is [BHU 1997]

Options:

A) $\frac{4}{3 \times 10967} c m$

B) $\frac{3}{4 \times 10967} c m$

C) $\frac{4 \times 10967}{3} c m$

D) $\frac{3}{4} \times 10967 c m$

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Answer:

Correct Answer: A

Solution:

$\frac{1}{λ} = R_{H} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}] .$

For Lyman series n1=1 and n2=2, 3, 4,

When n2=2, we get $λ = \frac{4}{3 R_{H}} = \frac{4}{3 \times 10967} c m$

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Atoms And Nuclei Question 74

Question: The wavelength of Lyman series is [BHU 1997]

Options:

Answer:

Solution:

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