SATHEE: Atoms And Nuclei Question 73

Atoms And Nuclei Question 73

Question: The first line of Balmer series has wavelength 6563 Å. What will be the wavelength of the first member of Lyman series [RPMT 1996]

Options:

A) 1215.4 Å

B) 2500 Å

C) 7500 Å

D) 600 Å

Show Answer

Answer:

Correct Answer: A

Solution:

$\frac{1}{λ_{B a l m e r}} = R [\frac{1}{2^{2}} - \frac{1}{3^{2}}] = \frac{5 R}{36}$ , $\frac{1}{λ_{L y m a n}} = R [\frac{1}{1^{2}} - \frac{1}{2^{2}}] = \frac{3 R}{4}$
$∴ λ_{L y m a n} = λ_{B a l m e r} \times \frac{5}{27} = 1215.4 \AA$

Atoms And Nuclei Question 73

Question: The first line of Balmer series has wavelength 6563 Å. What will be the wavelength of the first member of Lyman series [RPMT 1996]

Options:

Answer:

Solution:

Engineering Preparation

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Atoms And Nuclei Question 73

Question: The first line of Balmer series has wavelength 6563 Å. What will be the wavelength of the first member of Lyman series [RPMT 1996]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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