Atoms And Nuclei Question 53

Question: According to Bohr’s theory the moment of momentum of an electron revolving in second orbit of hydrogen atom will be [MP PET 1999; KCET 2003]

Options:

A) $ 2\pi h $

B) $ \pi h $

C) $ \frac{h}{\pi } $

D) $ \frac{2h}{\pi } $

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Answer:

Correct Answer: C

Solution:

Angular momentum $ L=n( \frac{h}{2\pi } ) $ For this case n=2, hence $ L=2\times \frac{h}{2\pi }=\frac{h}{\pi } $



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