Atoms And Nuclei Question 50

Question: Ratio of the wavelengths of first line of Lyman series and first line of Balmer series is [EAMCET (Engg.) 1995; MP PMT 1997]

Options:

A) 1: 3

B) 27 : 5

C) 5 : 27

D) 4 : 9

Show Answer

Answer:

Correct Answer: C

Solution:

$ \frac{1}{\lambda }=R( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} ) $

For first line of Lymen series n1 = 1 and n2 = 2

For first line of Balmer series n2 = 2 and n2 = 3

So, $ \frac{{\lambda_{Lymen}}}{{\lambda_{Balmer}}}=\frac{5}{27} $



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