Atoms And Nuclei Question 444

Question: The wavelength of the energy emitted when electron come from fourth orbit to second orbit in hydrogen is 20.397,cm . The wavelength of energy for the same transition in He+ is

Options:

A) 5.099 cm1

B) 20.497 cm1

C) 40.994 cm1

D) 81.988 cm1

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Answer:

Correct Answer: A

Solution:

  • E(=hcλ)Z2n2
    Þ λ1Z2 Hence λHe+=20.3974=5.099,cm


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