SATHEE: Atoms And Nuclei Question 442

Atoms And Nuclei Question 442

Question: The extreme wavelengths of Paschen series are

Options:

A) $0.365 μ m$ and $0.565 μ m$

B) $0.818 μ m$ and $1.89 μ m$

C) $1.45 μ m$ and $4.04 μ m$

D) $2.27 μ m$ and $7.43 μ m$

Show Answer

Answer:

Correct Answer: B

Solution:

(b) In Paschen series
$\frac{1}{λ_{max}} = R [\frac{1}{{(3)}^{2}} - \frac{1}{{(4)}^{2}}]$

Þ $λ_{max} = \frac{144}{7 R} = \frac{144}{7 \times 1.1 \times 10^{7}} = 1.89 \times 10^{- 6} m = 1.89, μ m$ Similarly
$λ_{min} = \frac{9}{R} = \frac{9}{1.1 \times 10^{7}} = 0.818, μ m$

Atoms And Nuclei Question 442

Question: The extreme wavelengths of Paschen series are

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

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Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Atoms And Nuclei Question 442

Question: The extreme wavelengths of Paschen series are

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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