Atoms And Nuclei Question 441

Question: The velocity of an electron in the second orbit of sodium atom (atomic number = 11) is v. The velocity of an electron in its fifth orbit will be

Options:

A) v

B) $ \frac{22}{5}v $

C) $ \frac{5}{2}v $

D) $ \frac{2}{5}v $

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Answer:

Correct Answer: D

Solution:

  • vn $ \propto \frac{1}{n} $
    Þ $ \frac{v_{5}}{v_{2}}=\frac{2}{5}\Rightarrow v_{5}=\frac{2}{5}v_{2}=\frac{2}{5}v $


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