SATHEE: Atoms And Nuclei Question 440

Atoms And Nuclei Question 440

Question: According to Bohr’s theory, the expressions for the kinetic and potential energy of an electron revolving in an orbit is given respectively by

Options:

A) $+ \frac{e^{2}}{8 π ε_{0} r}$ and $- \frac{e^{2}}{4 π ε_{0} r}$

B) $+ \frac{8 π ε_{0} e^{2}}{r}$ and $- \frac{4 π ε_{0} e^{2}}{r}$

C) $- \frac{e^{2}}{8 π ε_{0} r}$ and $- \frac{e^{2}}{4 π ε_{0} r}$

D) $+ \frac{e^{2}}{8 π ε_{0} r}$ and $+ \frac{e^{2}}{4 π ε_{0} r}$

Show Answer

Answer:

Correct Answer: A

Solution:

P.E. $= - \frac{k e^{2}}{r} = - \frac{e^{2}}{4 π ε_{0} r}$ ; K.E. $= - \frac{1}{2} (P .E .) = \frac{e^{2}}{8 π ε_{0} r}$

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Atoms And Nuclei Question 440

Question: According to Bohr’s theory, the expressions for the kinetic and potential energy of an electron revolving in an orbit is given respectively by

Options:

Answer:

Solution:

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