Atoms And Nuclei Question 44

Question: In terms of Rydberg’s constant R, the wave number of the first Balmer line is [MP PMT 1996]

Options:

A) R

B) 3R

C) $ \frac{5R}{36} $

D) $ \frac{8R}{9} $

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Answer:

Correct Answer: C

Solution:

Wave number $ =\frac{1}{\lambda }=R( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} ) $ For first Balmer line n1= 2, n2=3
$ \therefore $ Wave number $ =R( \frac{1}{2^{2}}-\frac{1}{3^{2}} )=R( \frac{9-4}{9\times 4} )=\frac{5R}{36} $



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