SATHEE: Atoms And Nuclei Question 354

Atoms And Nuclei Question 354

Question: Consider the following reaction $_{1} H^{2} +_{1} H^{2} \to_{2} H^{4} + Q .$ If $m,_{1} H^{2} = 2.014 l a m u;$ $m,_{2} H^{4} = 4.0024 l a m u .$ The energy Q released (in MeV) in this fusion reaction is

Options:

A) 12

B) 6

C) 24

D) 48

Show Answer

Answer:

Correct Answer: C

Solution:

$_{1} H^{2} +_{1} H^{2} \to_{2} H e^{4} + Q$

$\Rightarrow Δ m = m_{2} H e^{4} - 2 m_{1} H^{2}$

$\Rightarrow Δ m = 4.0024 - 2 (2.0141)$
$\Rightarrow Δ m = - 0.0258, a m u$ Since, $Q = c^{2} Δ m$
$\Rightarrow, Q = (0.0258) (931.5) M e V \Rightarrow Q = 24, M e V .$

Atoms And Nuclei Question 354

Question: Consider the following reaction $_{1} H^{2} +_{1} H^{2} \to_{2} H^{4} + Q .$ If $m,_{1} H^{2} = 2.014 l a m u;$ $m,_{2} H^{4} = 4.0024 l a m u .$ The energy Q released (in MeV) in this fusion reaction is

Options:

Answer:

Solution:

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Atoms And Nuclei Question 354

Question: Consider the following reaction 1H2+1H2→2H4+Q. If m,1H2=2.014lamu; m,2H4=4.0024lamu. The energy Q released (in MeV) in this fusion reaction is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Consider the following reaction $_{1} H^{2} +_{1} H^{2} \to_{2} H^{4} + Q .$ If $m,_{1} H^{2} = 2.014 l a m u;$ $m,_{2} H^{4} = 4.0024 l a m u .$ The energy Q released (in MeV) in this fusion reaction is