Atoms And Nuclei Question 353
Question: Imagine that a reactor converts all given mass into energy and that it operates at a power level of 109 watt. The mass of the fuel consumed per hour in the reactor will be : (velocity of light, c is $ 3\times 10^{8}m/s $ )
Options:
A) $ 0.96gm $
B) $ 0.8gm, $
C) $ 4\times {{10}^{-2}}gm~~~~~ $
D) $ 6.6\times {{10}^{-5}}gm $
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Answer:
Correct Answer: C
Solution:
- Power level of reactor, $ P=\frac{E}{\Delta t}=\frac{\Delta mc^{2}}{\Delta t} $ mass of the fuel consumed per hour in the reactor, $ \frac{\Delta m}{\Delta t}=\frac{P}{c^{2}}=\frac{10^{9}}{{{(3\times 10^{8})}^{2}}}kg/\sec =\frac{3600\times 10^{9}}{9\times 10^{16}} $ $ \times 10^{3}\frac{gm}{hr} $
