Atoms And Nuclei Question 351

Question: In the sun about 4 billion kg of matter is converted to energy each second. The power output of the sun in watt is

Options:

A) $ ~3.6\times 10^{26} $

B) $ 0.36\times 10^{26} $

C) $ 36\times 10^{26} $

D) $ 0.0036\times 10^{26} $

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Answer:

Correct Answer: B

Solution:

  • $ \frac{m}{t}=4\times 10^{8}kg{{s}^{-1}} $ $ E=mc^{2} $
    $ \Rightarrow \frac{E}{t}=( \frac{m}{t} )c^{2}\Rightarrow \frac{E}{t}=4\times 10^{8}\times 9\times 10^{16} $
    $ \Rightarrow \frac{E}{t}=3.6\times 10^{25}J{{s}^{-1}}\Rightarrow \frac{E}{t}=3.6\times 10^{25}W $


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