Atoms And Nuclei Question 340
Question: The masses of neutron and proton are 1.0087 a.m.u. and 1.0073 a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 a.m.u the binding energy of the helium nucleus will be $ ( 1a.m.u.=931MeV ) $
Options:
A) 28.4 MeV
B) 20.8 MeV
C) 27.3 MeV
D) 14.2 MeV
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Answer:
Correct Answer: A
Solution:
- $ B.E.=\Delta mc^{2}=\Delta \times 931MeV $ $ =[2(1.0087+1.0073)-4.0015]\times 931 $ $ =28.4,MeV $
