Atoms And Nuclei Question 336

Question: The binding energy of deuteron 12H is 1.15 A MeV per nucleon and an alpha particle 24He has a binding energy of 7.1 MeV per nucleon. Then in the reaction 12He+12He22He+Q the energy released Q is:

Options:

A) 5.95 MeV

B) 26.1 MeV

C) 23.8 MeV

D) 289.4 MeV

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Answer:

Correct Answer: C

Solution:

  • Given, 1H2+1H22H4+Q

The total binding energy of the deutrons

=4×1.15=4.60,MeV

The total binding energy of alpha particle =4×7.1=28.4,MeV

The energy released in the process =28.44.60=23.8,MeV .



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