Atoms And Nuclei Question 335

Question: Calculate binding energy of 92U238 . Given MU238=238.050783amu mn=1.008665amu and mp=1.007825amu

Options:

A) 801.7MeV

B) 18.7 MeV

C) 0.7 MeV

D) 1801.7 MeV.

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Answer:

Correct Answer: D

Solution:

  • Mass defect Δm=[Zmp+(AZ)mn]M(U238)
    =[92×1.007825(23892)×1.008665]

238.050783 Δm=1.93421,amu

BE=1.93421×931.5,MeV=1801.7,MeV



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