SATHEE: Atoms And Nuclei Question 334

Atoms And Nuclei Question 334

Question: The radius of germanium $(G e)$ nuclide is measured to be twice the radius of $_{4}^{9} B e$ . The number of nucleons in $G e$ are

Options:

A) 74

B) 75

C) 72

D) 73

Show Answer

Answer:

Correct Answer: C

Solution:

We use the formula, $R = R_{0} A^{1 / 3}$

This represents relation between atomic mass and radius of the nucleus.

For berillium, $R_{1} = R_{0} {(9)}^{1 / 3}$ For germanium, $R_{2} = R_{0} A^{1 / 3}$

$\frac{R_{1}}{R_{2}} = \frac{{(9)}^{1 / 3}}{{(A)}^{1 / 3}} \Rightarrow \frac{1}{2} = \frac{{(9)}^{1 / 3}}{{(A)}^{1 / 3}}$
$\Rightarrow, \frac{1}{8} = \frac{9}{A} \Rightarrow A = 8 \times 9 = 72.$

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Atoms And Nuclei Question 334

Question: The radius of germanium (Ge) nuclide is measured to be twice the radius of 49Be . The number of nucleons in Ge are

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Question: The radius of germanium $(G e)$ nuclide is measured to be twice the radius of $_{4}^{9} B e$ . The number of nucleons in $G e$ are