Atoms And Nuclei Question 333

Question: If the nucleus 1327Al has nuclear radius of about 3.6 fm, then 32125Te would have its radius approximately as

Options:

A) 9.6 fm

B) 12.0 fm

C) 4.8 fm

D) 6.0 fm.

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Answer:

Correct Answer: D

Solution:

  • It has been known that a nucleus of mass number A has radius

R=R0A1/3,

where R0=1.2×1015m

and A = mass number In case of 1327A,

let nuclear radius be R1 and for 32125Te,

nuclear radius be R2

For 1327Al,,R1=R0(27)1/3=3R0

For 32125Te,R2=R0(125)1/3=5R0 R2R1=5R03R0=53R1=53×3.6=6fm



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