Atoms And Nuclei Question 331

Question: The nuclear radius of a nucleus with nucleon number 16 is $ 3\times {{10}^{-15}}m $ . Then, the nuclear radius of a nucleus with nucleon number 128 is

Options:

A) $ 3\times {{10}^{-15}}m $

B) $ 1.5\times {{10}^{-15}}m $

C) $ 6\times {{10}^{-15}}m $

D) $ 4.5\times {{10}^{-15}}m $

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Answer:

Correct Answer: C

Solution:

  • Radius R os a nucleus changes with the nucleon number A of the nucleus as
    $ R=1.3\times {{10}^{-15}}\times {{A}^{1/3}}m $

Hence, $ \frac{R_{2}}{R_{1}}={{( \frac{A_{2}}{A_{1}} )}^{1/3}}={{( \frac{128}{16} )}^{1/3}}={{(8)}^{1/3}}=2 $
$ \therefore R_{2}=2R_{1}=2(3\times {{10}^{-15}})m=6\times {{10}^{-15}}m $



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