Atoms And Nuclei Question 329
Question: The nuclear radius of $ _{8}O^{16} $ is $ 3\times {{10}^{-15}} $ . If an atomic mass unit is $ 1.67\times {{10}^{-27}}kg $ , then the nuclear density is approximately
Options:
A) $ 2.35\times 10^{17}g/c{{m}^{-3}} $
B) $ 2.35\times 10^{17}kg/c{{m}^{-3}} $
C) $ 2.35\times 10^{17}c{{m}^{-3}} $
D) $ 2.35\times 10^{17}kgm{{m}^{-3}} $
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Answer:
Correct Answer: B
Solution:
- For nucleus of $ _{8}O^{16} $ Mass $ =(16),(1.67\times {{10}^{-27}})kg $
Volume $ =\frac{4}{3}\pi R^{3} $
$ =\frac{4}{3}\pi {{(3\times {{10}^{-15}})}^{3}}m^{3}=36\pi \times {{10}^{-45}}m^{3} $
Density $ =\frac{mass}{volume}=\frac{16\times 1.67\times {{10}^{-27}}kg}{36\pi \times {{10}^{-45}}m^{3}} $ $ =2.35\times 10^{17}kg{{m}^{-3}} $
