SATHEE: Atoms And Nuclei Question 309

Atoms And Nuclei Question 309

Question: Ultraviolet light of wavelengths $λ_{1}$ and $λ_{2}$ when allowed to fall on hydrogen atoms in their ground state is found to liberate electrons with kinetic energy $K . E_{1}$ and $K . E_{2}$ respectively. Find the value of Planck’s constant.

Options:

A) $h = | \frac{(K . E_{2} - K . E_{1}) (λ_{1} + λ_{2})}{C (λ_{1} - λ_{2})} |$

B) $h = | \frac{(K . E_{1} - K . E_{2}) (λ_{2} - λ_{1})}{C λ_{1} λ_{2}} |$

C) $h = | \frac{(K . E_{1} - K . E_{2}) λ_{1} λ_{2}}{C (λ_{2} - λ_{1})} |$

D) None of These

Show Answer

Answer:

Correct Answer: C

Solution:

$\frac{h c}{λ_{1}} - \frac{h c}{λ_{0}} = K . E ._{1} and \frac{h c}{λ_{2}} - \frac{h c}{λ_{0}} = K . E ._{2}$
$\Rightarrow \frac{h c}{λ_{1}} - \frac{h c}{λ_{2}} = K . E ._{1} - K . E ._{2}$

$\Rightarrow h c [\frac{λ_{2} - λ_{1}}{λ_{1} λ_{2}}] = K . E ._{1} - K . E ._{2}$

$∴ h = \frac{(K . E ._{1} - K . E ._{2}) λ_{1} λ_{2}}{c (λ_{2} - λ_{1})}$

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Atoms And Nuclei Question 309

Question: Ultraviolet light of wavelengths λ1 and λ2 when allowed to fall on hydrogen atoms in their ground state is found to liberate electrons with kinetic energy K.E1 and K.E2 respectively. Find the value of Planck’s constant.

Options:

Answer:

Solution:

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Question: Ultraviolet light of wavelengths $λ_{1}$ and $λ_{2}$ when allowed to fall on hydrogen atoms in their ground state is found to liberate electrons with kinetic energy $K . E_{1}$ and $K . E_{2}$ respectively. Find the value of Planck’s constant.