Atoms And Nuclei Question 299

Question: The ionization energy of a hydrogen-like Bohr atom is 4 Rydbergs. Find the wavelength of radiation emitted when the electron jumps from the first excited state to the ground state: [1 Rydberg =2.2×1018,h=6.6×1034Js, c=3×108m/s . Bohr radius of hydrogen atom =5×1011m

Options:

A) 400Ao,

B) 300Ao,

C) 500Ao,

D) 600Ao,

Show Answer

Answer:

Correct Answer: B

Solution:

  • The energy in the ground state E1=,4Rydberg E1=,4×2.2×1018J The energy of the first excited state (n=2) E2=E14=2.2×1018J The energy difference ΔE=E2E1=3×2.2×1018J Now, the wavelength of radiation emitted is λ=hcΔE λ=6.6×1034×3×1083×2.2×1018=300Ao,


NCERT Chapter Video Solution

Dual Pane