Atoms And Nuclei Question 294

Question: Which of the following transitions in hydrogen atoms emit photons of highest frequency?

Options:

A) n=1 to n=2

B) n=2 to n=6

C) n=6 to n=2

D) n=2 to n=l

Show Answer

Answer:

Correct Answer: D

Solution:

  • Frequency is given by $ hv=-13.6( \frac{1}{n _{1}^{2}}+\frac{1}{n _{2}^{2}} ) $

    For transition from n=6 to n=2, $ v _{1}=\frac{-13.6}{h}( \frac{1}{6^{2}}-\frac{1}{2^{2}} )=\frac{2}{9}\times ( \frac{13.6}{h} ) $

    For transition from n=2 to n=1, $ v _{2}=\frac{-13.6}{h}( \frac{1}{2^{2}}-\frac{1}{1^{2}} )=\frac{3}{4}\times ( \frac{13.6}{h} ). $
    $ \therefore v _{1}>v _{2} $



NCERT Chapter Video Solution

Dual Pane