Atoms And Nuclei Question 289

Question: An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom. The energy (in eV) required to remove both the electrons from a neutral helium atom is

Options:

A) 38.2

B) 49.2

C) 51.8

D) 79.0

Show Answer

Answer:

Correct Answer: D

Solution:

  • For helium ion, Z=2 and for first orbit n=1

$ \therefore E_{1}=\frac{-13.6}{{{( 1 )}^{2}}}\times 2^{2}=-54.4eV $

$ \therefore $ Energy required to remove this $ {{e}^{-}}=+54.4eV $

$ \therefore $ Total energy required $ =54.4+24.6=79eV $



NCERT Chapter Video Solution

Dual Pane