Atoms And Nuclei Question 288

Question: Consider 3rd orbit of He+ (Helium), using non-relativistic approach, the speed of electron in this orbit will be [given K=9×109 constant and h (Plank’s Constant) 6.6×1034Js ]

Options:

A) 1.46×106m/s

B) 0.73×106m/s

C) 3.0×108m/s

D) 2.92×106m/s

Show Answer

Answer:

Correct Answer: A

Solution:

  • Speed of electron in nth orbit Vn=2πKZe2nh

    V=(2.19×106m/s)Zn V=(2.19×106)23(Z=2&n=3)

    V=1.46×106m/s



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