SATHEE: Atoms And Nuclei Question 286

Atoms And Nuclei Question 286

Question: In a Rutherford experiment, the number of particles scattered at $90^{\circ}$ angle are 28 per minute then number of scattered particles at an angle $60^{\circ}$ and $120^{\circ}$ will be

Options:

A) 117 per minute, 25 per minute

B) 50 per minute, 12.5 per minute

C) 100 per minute, 200 per minute

D) 112 per minute, 12.4 per minute

Show Answer

Answer:

Correct Answer: D

Solution:

No. of particles scattered through an angle

$θ = N (θ) = \frac{k Z^{2}}{\sin^{4} (\frac{θ}{2}) {(K . E .)}^{2}}$

$∴ 28 = \frac{4 k c z^{2}}{{(K . E .)}^{2}} for θ =90^{\circ}$

$∴ \frac{k c z^{2}}{{(K . E .)}^{2}} = \frac{28}{4} = 7$

$∴ N (60^{\circ}) = \frac{7}{\sin^{4} (\frac{60^{\circ}}{2})} = 16 \times 7 = 112 / min .$ $N (120^{\circ}) = \frac{7}{\sin (\frac{120^{\circ}}{2})} = 12.4 / min$

Atoms And Nuclei Question 286

Question: In a Rutherford experiment, the number of particles scattered at $90^{\circ}$ angle are 28 per minute then number of scattered particles at an angle $60^{\circ}$ and $120^{\circ}$ will be

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Atoms And Nuclei Question 286

Question: In a Rutherford experiment, the number of particles scattered at 90∘ angle are 28 per minute then number of scattered particles at an angle 60∘ and 120∘ will be

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: In a Rutherford experiment, the number of particles scattered at $90^{\circ}$ angle are 28 per minute then number of scattered particles at an angle $60^{\circ}$ and $120^{\circ}$ will be