SATHEE: Atoms And Nuclei Question 284

Atoms And Nuclei Question 284

Question: If the angular momentum of an electron in an orbit is J then the K.E. of the electron in that orbit is

Options:

A) $\frac{J^{2}}{2 m r^{2}}$

B) $\frac{J v}{r}$

C) $\frac{J^{2}}{2 m}$

D) $\frac{J^{2}}{2 π}$

Show Answer

Answer:

Correct Answer: A

Solution:

Angular momentum $= m r v = J ∴ v = \frac{J^{2}}{2 m r^{2}}$ $K .E . of electron= \frac{1}{2} m v^{2} = \frac{1}{2} m {(\frac{J}{m r})}^{2} = \frac{J^{2}}{2 m r^{2}}$

Atoms And Nuclei Question 284

Question: If the angular momentum of an electron in an orbit is J then the K.E. of the electron in that orbit is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

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Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Atoms And Nuclei Question 284

Question: If the angular momentum of an electron in an orbit is J then the K.E. of the electron in that orbit is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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