Atoms And Nuclei Question 280

Question: Suppose that a material emits X-rays of wavelengths λκα,λκβ,λLα , when it is excited by fast moving electrons; the wavelengths corresponding to Kα,Kβ,Lα X- rays of the material respectively. Then we can write

Options:

A) λκβ=λκα+λLα

B) λκβ=λκα+λLα

C) 1λκβ=1λκα+1λLα

D) 1λκβ=1λκα+1λLα

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Answer:

Correct Answer: C

Solution:

  • The energy level diagram of the atom is . It is clear that Eκβ=Eκα+ELα or,vκβ=vκα+vLα or,1λκβ=1λκα+1λLα


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