SATHEE: Atoms And Nuclei Question 28

Atoms And Nuclei Question 28

Question: If m is mass of electron, v its velocity, r the radius of stationary circular orbit around a nucleus with charge Ze, then from Bohr’s first postulate, the kinetic energy $K = \frac{1}{2} m v^{2}$ of the electron in C.G.S. system is equal to [NCERT 1977]

Options:

A) $\frac{1}{2} \frac{Z e^{2}}{r}$

B) $\frac{1}{2} \frac{Z e^{2}}{r^{2}}$

C) $\frac{Z e^{2}}{r}$

D) $\frac{Z e}{r^{2}}$

Show Answer

Answer:

Correct Answer: A

Solution:

In the revolution of electron, coulomb force provides the necessary centripetal force Þ $\frac{z e^{2}}{r^{2}} = \frac{m v^{2}}{r}$
Þ $m v^{2} = \frac{z e^{2}}{r}$ \ K.E. $= \frac{1}{2} m v^{2} = \frac{z e^{2}}{2 r}$

Atoms And Nuclei Question 28

Question: If m is mass of electron, v its velocity, r the radius of stationary circular orbit around a nucleus with charge Ze, then from Bohr’s first postulate, the kinetic energy $K = \frac{1}{2} m v^{2}$ of the electron in C.G.S. system is equal to [NCERT 1977]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Atoms And Nuclei Question 28

Question: If m is mass of electron, v its velocity, r the radius of stationary circular orbit around a nucleus with charge Ze, then from Bohr’s first postulate, the kinetic energy K=12mv2 of the electron in C.G.S. system is equal to [NCERT 1977]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question: If m is mass of electron, v its velocity, r the radius of stationary circular orbit around a nucleus with charge Ze, then from Bohr’s first postulate, the kinetic energy $K = \frac{1}{2} m v^{2}$ of the electron in C.G.S. system is equal to [NCERT 1977]