SATHEE: Atoms And Nuclei Question 257

Atoms And Nuclei Question 257

Question: The energy in MeV is released due to transformation of 1 kg mass completely into energy $(c = 3 \times 10^{8} m / s)$ [Pb. PMT 2003]

Options:

A) $7.625 \times 10, M e V$

B) $10.5 \times 10^{29}, M e V$

C) $2.8 \times 10^{- 28}, M e V$

D) $5.625 \times 10^{29}, M e V$

Show Answer

Answer:

Correct Answer: D

Solution:

$E = Δ m c^{2} = 1 \times {(3 \times 10^{8})}^{2} = 9 \times 10^{10} J$
$\Rightarrow E = \frac{9 \times 10^{16}}{1.6 \times 10^{- 19}} = 5.625 \times 10^{35} e V$ $= 5.625 \times 10^{29} M e V .$

Atoms And Nuclei Question 257

Question: The energy in MeV is released due to transformation of 1 kg mass completely into energy $(c = 3 \times 10^{8} m / s)$ [Pb. PMT 2003]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Atoms And Nuclei Question 257

Question: The energy in MeV is released due to transformation of 1 kg mass completely into energy (c=3×108m/s) [Pb. PMT 2003]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The energy in MeV is released due to transformation of 1 kg mass completely into energy $(c = 3 \times 10^{8} m / s)$ [Pb. PMT 2003]