SATHEE: Atoms And Nuclei Question 242

Atoms And Nuclei Question 242

Question: The nuclear reaction $^{2} H +^{2} H \to,^{4} H e$ (mass of deuteron = 2.0141 a.m.u. and mass of He = 4.0024 a.m.u.) is [Orissa JEE 2002]

Options:

A) Fusion reaction releasing 24 MeV energy

B) Fusion reaction absorbing 24 MeV energy

C) Fission reaction releasing 0.0258 MeV energy

D) Fission reaction absorbing 0.0258 MeV energy

Show Answer

Answer:

Correct Answer: A

Solution:

Total mass of reactants

$= (2.0141) \times 2 = 4.0282 a m u$

Total mass of products $= 4.0024 a m u$ M

ass defect $= 4.0282 a m u - 4.0024 a m u$ $= 0.0258 a m u$
$∴$ Energy released $E = 931 \times 0.0258 = 24 M e V$

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Atoms And Nuclei Question 242

Question: The nuclear reaction 2H+2H→,4He (mass of deuteron = 2.0141 a.m.u. and mass of He = 4.0024 a.m.u.) is [Orissa JEE 2002]

Options:

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Question: The nuclear reaction $^{2} H +^{2} H \to,^{4} H e$ (mass of deuteron = 2.0141 a.m.u. and mass of He = 4.0024 a.m.u.) is [Orissa JEE 2002]