Atoms And Nuclei Question 191
Question: The mass defect in a particular nuclear reaction is 0.3 grams. The amount of energy liberated in kilowatt hours is (Velocity of light = $ 3\times 10^{8},m/s $ ) [EAMCET 2003]
Options:
A) $ 1.5\times 10^{6} $
B) $ 2.5\times 10^{6} $
C) $ 3\times 10^{6} $
D) $ 7.5\times 10^{6} $
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Answer:
Correct Answer: D
Solution:
$ E=\Delta m.c^{2} $
$ \Rightarrow E=\frac{0.3}{1000}\times {{(3\times 10^{8})}^{2}}=2.7\times 10^{13}J $ $ =\frac{2.7\times 10^{13}}{3.6\times 10^{6}}=7.5\times 10^{6}kWh $ .
